U=(X-A)/C; A=25; C=0.5 konarak,
U1=(23.5-25)/0.5=-1.5/0.5=-3 bulunur.
Aynı şekilde tabloyu yeniden düzenlersek;
|
U
|
f
|
fU
|
U2
|
f U2
|
f(U+1)2
|
|
-3
|
1
|
-3
|
9
|
9
|
4
|
|
-2
|
6
|
-12
|
4
|
24
|
6
|
|
-1
|
23
|
-23
|
1
|
23
|
0
|
|
0
|
48
|
0
|
0
|
0
|
48
|
|
+1
|
39
|
39
|
1
|
39
|
156
|
|
+2
|
20
|
40
|
4
|
80
|
180
|
|
+3
|
5
|
15
|
9
|
45
|
80
|
|
+4
|
2
|
8
|
16
|
32
|
50
|
|
|
∑f=144
|
∑fU=64
|
|
∑fU2=252
|
∑f(U+1)2=524
|
U=(∑fU)/f=64/144=0.4444444
U2=0.197530864
σU2=(∑fU2)/n-U2=252/144-0.1975=1.75-0.1975
σU=√1.552569136=1.245981
σX=C*σU=(0.5)*(1.245981)
σX=0.62299 bulunur…. |
